How to show that these sets are nonempty

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In summary: Additionally, the use of the axiom schema of separation guarantees that we are only considering k values that satisfy the given conditions. Therefore, by choosing a k value greater than the lower bound for each set, we can show that all three sets are nonempty. In summary, by choosing k values greater than their respective lower bounds, we can show that the sets R_{k,q}, S_{k,q}, and T_{k,q} are all nonempty.
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glebovg
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How to show that these sets are nonempty ([itex]\mid [/itex] means "divides")?

Here N is an arbitrary large integer and q is some fixed integer.

[itex]{R_{k,q}} = \{ k \in {\mathbb N}:(kN\mid k!) \wedge ((k - 1)N\mid k!) \wedge \cdots \wedge (N\mid k!) \wedge (k > Nq)\}[/itex]

[itex]{S_{k,q}} = \{ k \in {\mathbb N}:({(2k - 1)^2}N\mid k!) \wedge ({(2k - 3)^2}N\mid k!) \wedge \ldots \wedge (N\mid k!) \wedge (k > Nq)\}[/itex]

[itex]{T_{k,q}} = \{ k \in {\mathbb N}:({k^5}N\mid k!) \wedge ({(k - 1)^5}N\mid k!) \wedge \ldots \wedge (N\mid k!) \wedge (k > Nq)\}[/itex]

They exist by the axiom schema of separation, but how do I determine which [itex]k[/itex] to choose so that it satisfies all the properties? Is there a general approach?
 
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One approach is to note that for each set, there is a lower bound on the value of k that will guarantee that the set is nonempty. For R_{k,q}, since (kN\mid k!), we only need to consider k values greater than Nq. Similarly, for S_{k,q} and T_{k,q}, we need to consider k values greater than the square root of Nq and the fifth root of Nq respectively. This ensures that all of the sets are nonempty.
 

FAQ: How to show that these sets are nonempty

How can I prove that a set is nonempty?

To show that a set is nonempty, you can provide at least one element that belongs to the set. This can be done by either explicitly listing the elements of the set or by using logical reasoning to show that there must be at least one element in the set.

2. What is the importance of proving that a set is nonempty?

Proving that a set is nonempty is important because it establishes that there exists at least one element that satisfies the given conditions. This is crucial in mathematical and scientific reasoning, and it allows us to make meaningful conclusions and predictions based on the properties of the set.

3. Can a set be both empty and nonempty?

No, a set cannot be both empty and nonempty. A set is considered empty if it contains no elements, while a nonempty set must contain at least one element. These conditions are mutually exclusive, and a set must fall into one of these categories.

4. What are some common techniques for showing that a set is nonempty?

There are several techniques that can be used to show that a set is nonempty. Some common methods include using direct proofs, contradiction proofs, and proof by construction. Additionally, you can also use specific properties or characteristics of the set to show that it must contain at least one element.

5. How does proving a set is nonempty relate to the axiom of existence?

The axiom of existence, also known as the axiom of empty set, states that there exists a set with no elements. Proving that a set is nonempty is essentially the negation of this axiom, as it shows that there exists at least one element in the set. This is an important concept in set theory and mathematical logic.

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