How to Simplify a Square Root with Multiple Radicands

In summary, to simplify the expression \sqrt {10 + \sqrt{24} + \sqrt{40}+\sqrt{60}}, we use the equation \sqrt{a+b+2\sqrt{ab}} = \sqrt{a}+\sqrt{b}. We can see that the prime factors of 6, 10, and 15 are 2 and 3. By expanding the expression, we can rewrite it as \sqrt {10 + 2 \sqrt{6} + 2 \sqrt{10}+ 2 \sqrt{15}}. This can then be simplified using the equation to get the final result of \sqrt{6}+\sqrt{10}+\sqrt{15}.
  • #1
songoku
2,341
340

Homework Statement


Simplify

[tex]\sqrt {10 + \sqrt{24} + \sqrt{40}+\sqrt{60}}[/tex]


Homework Equations


[tex]\sqrt{a+b+2\sqrt{ab}} = \sqrt{a}+\sqrt{b}[/tex]


The Attempt at a Solution


[tex]\sqrt {10 + \sqrt{24} + \sqrt{40}+\sqrt{60}}[/tex]
[tex]= \sqrt {10 + 2 \sqrt{6} + 2 \sqrt{10}+ 2 \sqrt{15}}[/tex]

Stuck...
 
Physics news on Phys.org
  • #2
songoku said:

Homework Statement


Simplify
[tex]\sqrt {10 + \sqrt{24} + \sqrt{40}+\sqrt{60}}[/tex]

Homework Equations


[tex]\sqrt{a+b+2\sqrt{ab}} = \sqrt{a}+\sqrt{b}[/tex]

The Attempt at a Solution


[tex]\sqrt {10 + \sqrt{24} + \sqrt{40}+\sqrt{60}}[/tex]
[tex]= \sqrt {10 + 2 \sqrt{6} + 2 \sqrt{10}+ 2 \sqrt{15}}[/tex]
Stuck...
Why is it that [itex]\sqrt{a+b+2\sqrt{ab}} = \sqrt{a}+\sqrt{b}\,?[/itex]

It's because

[itex]a+b+2\sqrt{ab}=\sqrt{a}^2+2\sqrt{a}\sqrt{b}+\sqrt{b}^2[/itex]
[itex]\displaystyle=\left(\sqrt{a}+\sqrt{b}\right)^2[/itex]​

Now look at your final expression: [itex] \sqrt {10 + 2 \sqrt{6} + 2 \sqrt{10}+ 2 \sqrt{15}}\,.[/itex]

What are the prime factors of 6? ... of 10? ... of 15 ?

Expand [itex](x+y+z)^2\,.[/itex]
 
  • #3
SammyS, you are the greatest square-root simplifier!:biggrin:

ehild
 
  • #4
SammyS said:
Why is it that [itex]\sqrt{a+b+2\sqrt{ab}} = \sqrt{a}+\sqrt{b}\,?[/itex]

It's because

[itex]a+b+2\sqrt{ab}=\sqrt{a}^2+2\sqrt{a}\sqrt{b}+\sqrt{b}^2[/itex]
[itex]\displaystyle=\left(\sqrt{a}+\sqrt{b}\right)^2[/itex]​

Now look at your final expression: [itex] \sqrt {10 + 2 \sqrt{6} + 2 \sqrt{10}+ 2 \sqrt{15}}\,.[/itex]

What are the prime factors of 6? ... of 10? ... of 15 ?

Expand [itex](x+y+z)^2\,.[/itex]

Thanks :smile:

ehild said:
SammyS, you are the greatest square-root simplifier!:biggrin:

ehild

I agree :biggrin::approve:
 

FAQ: How to Simplify a Square Root with Multiple Radicands

What is a square root?

A square root is a number that, when multiplied by itself, gives the original number. For example, the square root of 25 is 5, because 5 x 5 = 25.

How do you simplify a square root?

To simplify a square root, you need to find the largest perfect square that is a factor of the number inside the square root sign. Then, you can take the square root of that perfect square and move it outside the square root sign. The remaining number inside the square root sign is the simplified form.

Can all square roots be simplified?

No, not all square roots can be simplified. There are some numbers that do not have a perfect square as a factor, so they cannot be simplified further.

What is the difference between simplifying and evaluating a square root?

Simplifying a square root means rewriting it in its simplest form, while evaluating a square root means finding the numerical value of the square root. For example, simplifying the square root of 12 would give you √4 x √3, while evaluating it would give you the approximate value of 3.4641.

Why is it important to simplify square roots?

Simplifying square roots makes it easier to work with them in mathematical equations and to find approximate values without using a calculator. It can also help in finding patterns and relationships between numbers.

Similar threads

Back
Top