- #1
mathdad
- 1,283
- 1
Solve the log equation
log_16 (3x-1)=log_4 (3x) + log_4 (0.5)
Can someone get me started?
The left side has base 16 and the right side base 4.
How is this done when two different bases are involved?
log_16 (3x-1)=log_4 (3x) + log_4 (0.5)
Can someone get me started?
The left side has base 16 and the right side base 4.
How is this done when two different bases are involved?