- #1
mcintyre_ie
- 66
- 0
I’m having some difficulty with this question:
(b) A particle starts with a speed of 20 m/s and moves in a straight line. The particle is subjected to a resistance which produces a retardation which is initially 8 m/s^2 and which increases uniformly with the distance moved, having a value of 9 m/s^2 when the particle has moved a distance of 5 m.
If v m/s is the speed of the particle when it has moved a distance x m:
(i) prove that, while the particle is in motion,
v dv/dx = - ( 8 + x/5 )
(ii) Calculate the distance moved by the particle in coming to rest
I can’t seem to get out part (i), which is probably key to solving part (ii). I’m having problems with the force equation, more specifically with the resistance increasing with time/distance.
Thanks in advance for any help.
(b) A particle starts with a speed of 20 m/s and moves in a straight line. The particle is subjected to a resistance which produces a retardation which is initially 8 m/s^2 and which increases uniformly with the distance moved, having a value of 9 m/s^2 when the particle has moved a distance of 5 m.
If v m/s is the speed of the particle when it has moved a distance x m:
(i) prove that, while the particle is in motion,
v dv/dx = - ( 8 + x/5 )
(ii) Calculate the distance moved by the particle in coming to rest
I can’t seem to get out part (i), which is probably key to solving part (ii). I’m having problems with the force equation, more specifically with the resistance increasing with time/distance.
Thanks in advance for any help.