- #1
benjamince
- 6
- 0
Hi guys, this is my first post on the forums - I have a maths exam tomorrow and I'm pretty sure I will need to find the particular integral of a non-homogenous ODE. I find that pretty easy, but I'm not sure how to approach it when there are 2 different terms on the right:
d2y/dt2 - y = 1 + 3cos(2t)
or
(2)d2y/dt2 - dy/dt - y = t/2 + 3e(-t)
Any help would be much appreciated!
Thanks
Ben
d2y/dt2 - y = 1 + 3cos(2t)
or
(2)d2y/dt2 - dy/dt - y = t/2 + 3e(-t)
Any help would be much appreciated!
Thanks
Ben