- #1
hbk69
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Hi, i struggle to understand the topic which the following two questions come from? is it centre of gravity/equilibrium of forces? and what are the fundamental concepts/formula's involved in-order to solve the problems as i struggled to picture the problems. Thank you very much for any help. This is the first time i have approached these type of questions so wanted help which would help me answer similar problems in the future
1) Two men are carrying a 2m long 10 kg pole which from which is hung a 80 kg deer that they have shot. How far from the end of the pole should the deer be hung so that the weaker of the two men only supports half the load of the stronger?
Answer is (63 cm)
For this question, this was my attempt:
X= distance from how far the pole should
X= (2)(10) + (2)(80) / 10 + 90 = 2 cm
When they are asking for how far the deer is supposed to be hung so the weaker man supports half the load of the stronger what are they exactly asking me as i did not seem to understand? is it the centre of gravity? and how can i know who would be the weaker of the two? or are they just saying the weight of the deer is to be split between how much load each man would have to lift, so you'd have one man on one end and one man on the other with the deer in the middle so the questions asks to find the COG? if so how? but i am not sure i have understood the question correctly.
2) A uniform wooden beam 6 m long weighing 80 kg is lying horizontally on the floor. A builder raises one end until the beam is inclined at 300 to the horizontal and holds it in this position until his mate arrives to lift the other end. What is the magnitude of the force he exerts?
Answer is (346 N)
And for this question i was trying to think of the forces acting on the beam when the builder raises it, so you have mg=80kg, and then Fsinθ the horizontal component and Fcosθ the vertical component and then i was trying to think of how the resultant would be the force the builder uses to raise the beam and how 6m is supposed to be used
Thank you very much again, any help appreciated
1) Two men are carrying a 2m long 10 kg pole which from which is hung a 80 kg deer that they have shot. How far from the end of the pole should the deer be hung so that the weaker of the two men only supports half the load of the stronger?
Answer is (63 cm)
For this question, this was my attempt:
X= distance from how far the pole should
X= (2)(10) + (2)(80) / 10 + 90 = 2 cm
When they are asking for how far the deer is supposed to be hung so the weaker man supports half the load of the stronger what are they exactly asking me as i did not seem to understand? is it the centre of gravity? and how can i know who would be the weaker of the two? or are they just saying the weight of the deer is to be split between how much load each man would have to lift, so you'd have one man on one end and one man on the other with the deer in the middle so the questions asks to find the COG? if so how? but i am not sure i have understood the question correctly.
2) A uniform wooden beam 6 m long weighing 80 kg is lying horizontally on the floor. A builder raises one end until the beam is inclined at 300 to the horizontal and holds it in this position until his mate arrives to lift the other end. What is the magnitude of the force he exerts?
Answer is (346 N)
And for this question i was trying to think of the forces acting on the beam when the builder raises it, so you have mg=80kg, and then Fsinθ the horizontal component and Fcosθ the vertical component and then i was trying to think of how the resultant would be the force the builder uses to raise the beam and how 6m is supposed to be used
Thank you very much again, any help appreciated