- #1
tmt1
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- 0
I have this problem:
$\lim_{{t}\to{0}} \frac{tan(6t)}{sin2t}$
I know sin2t = 0 when t = 0, which means the original fraction is indeterminate, so how can apply the rules for limits to solve this limit?
$\lim_{{t}\to{0}} \frac{tan(6t)}{sin2t}$
I know sin2t = 0 when t = 0, which means the original fraction is indeterminate, so how can apply the rules for limits to solve this limit?