How to use residues with improper integrals?

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In summary, the integral of 1/(x^2+1) from 0 to infinity has a value of pi/2, which can be obtained by using the residue from the pole at z=i. The residue can be found by evaluating 1/(z+i) at z=i, which gives a value of 1/(2i). This can be simplified to pi/2 by multiplying by 1/2, as the function is even. The same concept can be applied to solve the integral of dx/(x^2+1)^2.
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laura_a
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Homework Statement



integral^infty_0 1/(x^2+1) (I know the answer (from text) is pi/2)


Homework Equations



Well that is what I need help with. I can see that there are 2 roots to the x^2+1 that are +/- i and I know from the text that I use the arc in the where x >= 0 so I use the z=i residue. I'm not sure what to do next in order to get the answer.

The Attempt at a Solution



I know that it is an even function so I can multiply the answer by 1/2 to get the value, and I also understand that the value of the integral is 2*pi*i *[Sum of residues]


Can anyone help me to understand. I have someone elses working out here on the same question and they are using limits and end up using ;im (z-i) = 1/2i
z->i (z-i)(z+i)

which I don't understand at all? How to get z-i and the other working out... it turns out that 1/2i is what I'm looking for because (1/2)2(pi)i(1/2i) is the answer... can anyone give me any extra info that might help me to understand, after this question I have to do the same thing but the question is dx/(x^2+1)^2 so I'm hoping that if I get help with the first one I'll understand the 2nd...

Thanks: :)
 
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Yes. You need to use the residue from the pole at z=i. Since 1/(z^2+1)=1/((z+i)*(z-i)), the residue is the value of this function after dropping the (z-i) factor evaluated at z=i. 1/(z+i) at z=i is 1/(2i). This is a good easy example to be clear about before you move on to harder ones.
 

FAQ: How to use residues with improper integrals?

What is a residue?

A residue is a complex number that is left over after the integration of a function with a singularity. It is typically found by calculating the limit of the function as it approaches the singularity.

How do you find the residues of improper integrals?

To find the residues of improper integrals, you can use the Residue Theorem or the Cauchy Residue Theorem. Both involve finding the poles of the function and using them to calculate the residues.

Can residues be used to evaluate improper integrals?

Yes, residues can be used to evaluate improper integrals, particularly those with simple poles. By using the Residue Theorem, the integral can be rewritten as a sum of the residues at each pole, making it easier to calculate.

What are some common techniques for dealing with residues in improper integrals?

Some common techniques for dealing with residues in improper integrals include using the Residue Theorem, Cauchy Residue Theorem, and the Method of Contour Integration. These techniques can help simplify the integration process and make it easier to evaluate the integral.

Are there any limitations to using residues in improper integrals?

Yes, there are some limitations to using residues in improper integrals. Residues can only be used for functions with simple poles, so they may not be applicable to all integrals. Additionally, the calculation of residues can be complex and time-consuming, making it difficult to use for certain integrals.

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