How would you simplify this logarithmic expression?

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In summary, the expression $\displaystyle \frac{1}{5}\ln|\sin5x|+\frac{1}{5}\ln|\csc5x-\cot5x|$ can be simplified to $\displaystyle \frac{1}{5}\ln\left|2\sin^2\! \tfrac{5x}{2}\right|$ through factoring, combining logarithms, distributing, and simplifying.
  • #1
paulmdrdo1
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how would you simplify this

$\displaystyle \frac{1}{5}\ln|\sin5x|+\frac{1}{5}\ln|\csc5x-\cot5x|$

please explain.
 
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  • #2
Re: simplification of expression

What have you tried?
 
  • #3
Re: simplification of expression

Ackbach said:
What have you tried?

i just factored out the 1/5 and I'm stucked.
 
  • #4
Re: simplification of expression

Hello Paul! Notice you can factor the $1/5$, yielding $$\frac{1}{5} \left[ \ln |\sin 5x | + \ln |\csc 5x - \cot 5x| \right],$$ and from here use that $\ln a + \ln b = \ln (ab)$. Consequently

$$\frac{1}{5} \left[ \ln |\sin 5x | + \ln |\csc 5x - \cot 5x| \right] = \frac{1}{5} \left[ \ln |\sin (5x) \cdot (\csc (5x) - \cot (5x) )| \right] = \frac{1}{5} \left[ \ln |1 - \cos (5x)| \right].$$

Cheers. :D
 
  • #5
Re: simplification of expression

Hello, paulmdrdo!

[tex]\text{Simplify: }\:\tfrac{1}{5}\ln|\sin5x|+\tfrac{1}{5}\ln|\csc5x-\cot5x|[/tex]

[tex]\begin{array}{ccc}\text{Factor:} & \tfrac{1}{5}\big(\ln|\sin5x| + \ln|\csc5x - \cot5x|\big) \\ \\ \text{Combine logs:} & \tfrac{1}{5}\ln|\sin5x(\csc5x - \cot5x)| \\ \\ \text{Distribute:} & \tfrac{1}{5}\ln|\sin5x\csc5x - \sin5x\cot5x| \\ \\ \text{Simplify:} & \tfrac{1}{5}\ln|1-\cos5x| \\ \\ \text{Further?} & \tfrac{1}{5}\ln\left|2\sin^2\! \tfrac{5x}{2}\right| \end{array}[/tex]
 
  • #6
Re: simplification of expression

soroban said:
Hello, paulmdrdo!


[tex]\begin{array}{ccc}\text{Factor:} & \tfrac{1}{5}\big(\ln|\sin5x| + \ln|\csc5x - \cot5x|\big) \\ \\ \text{Combine logs:} & \tfrac{1}{5}\ln|\sin5x(\csc5x - \cot5x)| \\ \\ \text{Distribute:} & \tfrac{1}{5}\ln|\sin5x\csc5x - \sin5x\cot5x| \\ \\ \text{Simplify:} & \tfrac{1}{5}\ln|1-\cos5x| \\ \\ \text{Further?} & \tfrac{1}{5}\ln\left|2\sin^2\! \tfrac{5x}{2}\right| \end{array}[/tex]

In the last step we can remove modulo sign as it positive
 

FAQ: How would you simplify this logarithmic expression?

What is simplification of expression?

Simplification of expression is a mathematical process of reducing an algebraic expression into a simpler form by combining like terms and using properties of operations.

Why is simplification of expression important?

Simplifying expressions allows for easier computation and understanding of mathematical equations. It also helps to identify patterns and relationships between different terms.

How do you simplify an algebraic expression?

To simplify an algebraic expression, you need to combine like terms by adding or subtracting coefficients, and using properties of operations such as the distributive property, commutative property, and associative property.

Can you give an example of simplifying an expression?

Yes, for example, the expression 3x + 2x can be simplified to 5x by combining the like terms 3x and 2x. Similarly, the expression 4(3x + 2) can be simplified to 12x + 8 by using the distributive property.

What are some common mistakes to avoid when simplifying expressions?

Some common mistakes to avoid when simplifying expressions include forgetting to combine like terms, not applying the correct properties of operations, and making calculation errors. It is important to double-check your work and use proper notation to avoid mistakes.

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