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why in 4.4 the author gave D =4Rh? in 4.5, D= 2Rh ? can you explain?Chestermiller said:
Yes. He is consistent in defining the hydraulic radius as S/Lp, and the equivalent diameter as 4S/Lp. However, in 4.5, he makes the mistake of calling the radius of the cylinder RH. The term in brackets should not have a subscript H. It should just have an R. And, for a cylinder, RH=R/2.foo9008 said:
Hydraulic diameter is a measure of the equivalent internal diameter of a non-circular conduit, and it is important because it allows for comparisons between different shapes and sizes of channels in fluid flow systems.
Hydraulic diameter is calculated by dividing four times the cross-sectional area of a channel by its wetted perimeter.
The difference between 4.4 and 4.5 hydraulic diameter is the shape of the channel. A 4.4 hydraulic diameter would refer to a circular channel, while a 4.5 hydraulic diameter would refer to a non-circular channel.
Hydraulic diameter affects fluid flow by determining the resistance to flow in a channel. A larger hydraulic diameter will result in lower resistance and therefore a higher flow rate, while a smaller hydraulic diameter will result in higher resistance and a lower flow rate.
Hydraulic diameter is used in engineering applications to calculate pressure drop, flow rate, and other important parameters in fluid flow systems. It is also used to determine the most efficient channel shape for a given flow rate and pressure drop.
