- #1
hotjohn
- 71
- 1
Homework Statement
i was told that the hydraulic diameter = 4Ac / p , while the hydraulic radius = Ac / p , where Ac = cross sectional area , and p = wetted perimeter of the pipe , why shouldn't the hydraulic radius = 2Ac / p ?
because as well all know , diameter = 2 Radius , so hydraulic radius = 2(hydraulic diameter ) = 2(4Ac / p) = 8Ac / p