Hydrogen bound by only grav force (Bohr theory etc)

In summary, the absence of electric charge would drastically alter the expressions for a_0 and E_n, with Bohr's radius becoming zero and E_n potentially being reduced to mc^2. The energy of the electron would solely be determined by the gravitational potential energy, and its angular momentum must still follow the Bohr model's principle.
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kpou
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Homework Statement


If electric charge did not exist, and protons and electrons were only bound together by gravitational forces to form hydrogen, derive the expressions for a_0 and E_n and compute the energy and frequency of the H_alpha line and limit of Balmer series.


Homework Equations


E_n=mc^2 * alpha * 1 / (2n^2)
E_n=-mk^2Z^2e^4/(2hbar*n^2)=-E_0Z^2/n^2
a_0=hbar^2/(mc*alpha)=hbar^2/mke^2
1/lambda=Z^2R(1/nf^2-1/ni^2)


The Attempt at a Solution


If electric charge did not exist, then the balance of electron orbit and distance would change. Bohr's radius would just be zero i would imagine since it depends on electron charge. E_n would suffer the same fate... Would E_n just become mc^2? The radius would have to still be a number as the two do still have mass and gravity would affect them.

Edit:
F=Gm1m2/r^2 is the force on either exerted by the other and
E=-Gm1m2/r is the gravitational potential energy

The energy of the electron E_n must be strictly dependent on this.

How do I "derive" an expression from E_n or a_0 when their original formulas must be completely nixed?

Is there supposed to be a way of expressing it with n levels?

Otherwise I propose the energy of the electron is -Gm1m2/r as there is no kinetic energy.
 
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One of the key components of the Bohr model is the electron's angular momentum must be an integer multiple of Planck's constant divided by 2 pi:

L = n h / 2 π . . . with n = 1, 2, 3, ...​
 

FAQ: Hydrogen bound by only grav force (Bohr theory etc)

What is the Bohr theory of hydrogen bound by only gravitational force?

The Bohr theory proposes that in a hypothetical scenario where only gravity is acting on a hydrogen atom, the electron would spiral into the nucleus due to the attractive force of gravity. This is in contrast to the actual behavior of hydrogen, where the electron is held in orbit by the electromagnetic force.

How does the Bohr theory explain the stability of atoms?

The Bohr theory suggests that the stability of atoms is due to the balance between the attractive gravitational force and the repulsive electromagnetic force between the positively charged nucleus and the negatively charged electrons. This balance results in stable orbits for the electrons.

Why is the Bohr theory not considered an accurate representation of hydrogen atoms?

The Bohr theory neglects the effects of quantum mechanics, which play a crucial role in understanding the behavior of atoms. It also does not take into account the strong nuclear force that holds the nucleus together. Therefore, it is not considered a complete and accurate representation of hydrogen atoms.

Can hydrogen atoms exist in a universe with only gravitational force?

No, hydrogen atoms cannot exist in a universe with only gravitational force. The absence of electromagnetic force would lead to the collapse of atoms, and the universe would consist of only a dense, compact mass of matter.

How does the Bohr theory relate to other models of the atom?

The Bohr theory was an important step in understanding the structure of atoms, but it has been superseded by more accurate and comprehensive models, such as the quantum mechanical model and the wave-mechanical model. These models take into account the effects of quantum mechanics and provide a more complete understanding of the behavior of atoms.

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