- #1
tosingoodnessamao
- 3
- 0
- Homework Statement
- If the velocity v of the air in a boundary layer having a dynamic viscosity of 18 × 10−6
kg/ms is given in terms of the distance y from the surface by:
v = ay + by^2
where a and b are constants, calculate the surface shear stress if at 1.5 mm from the surface
the velocity is 75 m/s, and at 3.0 mm from the surface it is 105 m/s.
I know that a is the shear strain/rate and i need to times it by the dynamic viscosity but i really cannot work out a and b.
* update - realised that I forgot to square the value for y when multiplying by b.
- Relevant Equations
- shear stress = (shear strain/rate) x du/dy
75 = (1.5 x 10^-3)a + (1.5 x 10^-3)b
105 = (3 x 10^-3)a + (3 x 10^-3)b
105 = (3 x 10^-3)a + (3 x 10^-3)b