I Have A Question about FUSION

[anias]

I Have A Question about FUSION! Please Help!

I Have A Question about FUSION! Please Help!

--------------------------------------------------------------------------------

the reaction of H and F produces about 500 kj/mol of energy:

how much energy is produced by the reaction of 2.0kg of H with 38 kg of F to produce 2 kmol of HF?

i know the answer is 5.0x 10 to the exponent 5 kJ... but I'm not sure why...


PLEASE HELP!
thanks for your time =D

 

[Astronuc]

Heat of Formation

This is a problem about the heat of formation, rather than fusion. In the context of chemistry, fusion usually refers to liquid to solid phase change.

Heat of fusion is the energy required for melting solids to liquids.

http://wine1.sb.fsu.edu/chm1045/notes/Energy/HeatForm/Energy05.htm

Now for the problem, which states heat of formation of HF is 500 kJ/mol.

The reaction is H₂ + F₂ -> 2 HF + Q, where Q = 500 KJ/mol, is the heat of formation.

You have 1 kmol of H₂ and 1 kmol of F₂, which yields 2 kmol of HF.

To solve the problem, one needs to know the basis of the heat of formation, i.e. the energy per mole.

 

[sir-pinski]

Hi there,

Thank you for reaching out with your question about FUSION. It seems like you are asking about the energy produced by the reaction of hydrogen and fluorine to form hydrogen fluoride (HF). This is a type of fusion reaction, where two smaller atoms combine to form a larger atom, releasing energy in the process.

To calculate the energy produced in this reaction, we need to use the equation E = mc^2, where E is energy, m is mass, and c is the speed of light. In this case, we are looking for the energy produced, so E is our unknown. The mass is given in kilograms, so we need to convert it to grams (1 kg = 1000 g). We also know that the speed of light is approximately 3.0 x 10^8 meters per second.

Plugging in these values, we get:

E = (2.0 kg + 38 kg) x (3.0 x 10^8 m/s)^2

E = 2.0 x 10^3 g x (9.0 x 10^16 m^2/s^2)

E = 1.8 x 10^20 g x m^2/s^2

Now, we need to convert this unit to joules (J), which is the standard unit for energy. We can do this by multiplying by the conversion factor 1 J = 1 kg x m^2/s^2.

E = 1.8 x 10^20 g x m^2/s^2 x (1 J/1 kg x m^2/s^2)

E = 1.8 x 10^20 J

However, this is the total energy produced by the reaction of 40 kg of hydrogen and fluorine. To find the energy produced by 2 kmol of HF, we need to divide this value by the number of moles of HF produced. 2 kmol is equal to 2 x 10^3 moles.

E = 1.8 x 10^20 J / (2 x 10^3 moles)

E = 9 x 10^16 J/mol

Now, to find the energy produced by the reaction of 2.0 kg of H with 38 kg of F to produce 2 kmol of HF, we need to multiply this value by 2 kmol.

E =