- #1
emadhamdy2002
- 1
- 0
Blending problem:
Decision variables
x1: tons of ore from mine 1 in each ton of the blend
x2: tons of ore from mine 2 in each ton of the blend
x3: tons of ore from mine 3 in each ton of the blend
x4: tons of ore from mine 4 in each ton of the blend
Objective function
Min cost
Min 800x1+400x2+600x3+500x4
Constraints
Element A: 10x1+3x2+8x3+2x4>=5
Element B: 90x1+250x2+75x3+175x4>=100
Element C: 45x1+25x2+20x3+37x4>=30
Weight: x1+x2+x3+x4=1
If you know that Element B has slack of 31.666
x1=0.259259
x2=0.703705
x3=0.037037
x4=0.00000
there is a question
what is the amount used of element B?compute it
i found a solution please if it is right can anyone explain it to me
90*0.259259+250*0.703705+75*0.037037+175*0-31.66=100
therefore the amount used =131.66
Can anyone Explain it to me?
Decision variables
x1: tons of ore from mine 1 in each ton of the blend
x2: tons of ore from mine 2 in each ton of the blend
x3: tons of ore from mine 3 in each ton of the blend
x4: tons of ore from mine 4 in each ton of the blend
Objective function
Min cost
Min 800x1+400x2+600x3+500x4
Constraints
Element A: 10x1+3x2+8x3+2x4>=5
Element B: 90x1+250x2+75x3+175x4>=100
Element C: 45x1+25x2+20x3+37x4>=30
Weight: x1+x2+x3+x4=1
If you know that Element B has slack of 31.666
x1=0.259259
x2=0.703705
x3=0.037037
x4=0.00000
there is a question
what is the amount used of element B?compute it
i found a solution please if it is right can anyone explain it to me
90*0.259259+250*0.703705+75*0.037037+175*0-31.66=100
therefore the amount used =131.66
Can anyone Explain it to me?