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gunitsoldier9
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Homework Statement
A parallel-plate capacitor has plates with an area of 410 cm^2 and an air-filled gap between the plates that is 2.00 mm thick. The capacitor is charged by a battery to 560 V and then is disconnected from the battery.
a.How much energy is stored in the capacitor?
b.The separation between the plates is now increased to 4.10 mm. How much energy is stored in the capacitor now?
c.How much work is required to increase the separation of the plates from 2.00 mm to 4.10 mm?
Homework Equations
C=(E0A/d)
U=1/2CV2
The Attempt at a Solution
I got part a but it keeps saying that part b is wrong when i do it the same way. I combined the first 2 eqns
U= 1/2(E0A/d)V2 for part A. Help please