I proving if a + a = 0 then a = 0

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In summary, the equation "a + a = 0" is trying to prove that if you add a number to itself and the result is 0, then the original number must be 0 as well. Proving this equation is important because it is a fundamental concept in mathematics and is used in many mathematical proofs and equations. It can be proved using the properties of addition and the fact that the inverse of any number is its negative. This equation can also be proven using mathematical induction. There are no exceptions to this equation, as it holds true for all real numbers.
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jmazurek
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I need help proving if a + a = 0 then a = 0. Thanks!
 
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Are you working with ordinary arithmetic, with ordinary (real or complex) numbers? If so then a+a=2a. Thus you have 2a=0. Divide both sides by 2 to get your answer.
 
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Sure, I'd be happy to help you with this proof. First, let's start by assuming that a + a = 0. This means that the sum of a and a is equal to 0. Now, we can use the properties of addition to rewrite this as a + a = a + (-a). This is because the additive inverse of a is -a, meaning that when added together, they cancel each other out and result in 0.

Next, we can use the associative property of addition to rearrange the terms and get (a + a) + (-a) = 0. Now, we know that a + a = 0, so we can substitute this in to get 0 + (-a) = 0. Again, using the additive inverse property, we can rewrite this as (-a) = 0.

Finally, we can use the additive identity property to conclude that a = 0. This is because the additive identity of any number is 0, meaning that when added to any number, it remains unchanged.

Therefore, we have proven that if a + a = 0, then a = 0. I hope this helps with your understanding of this proof. Let me know if you have any further questions.
 

FAQ: I proving if a + a = 0 then a = 0

What is the equation "a + a = 0" trying to prove?

This equation is trying to prove that if you add a number to itself and the result is 0, then the original number must be 0 as well.

Why is it important to prove this equation?

Proving this equation is important because it is a fundamental concept in mathematics and is used in many mathematical proofs and equations. It also helps to understand the properties of numbers and their relationships.

How can you prove that "a + a = 0" implies "a = 0"?

This can be proved using the properties of addition and the fact that the inverse of any number is its negative. By adding the inverse of a to both sides of the equation, we get a + a + (-a) = 0 + (-a). Simplifying this, we get 0 = -a. And since -a is the inverse of a, this means a must equal 0.

Can this equation be proven using mathematical induction?

Yes, this equation can be proven using mathematical induction. Induction is a method of mathematical proof that involves establishing a base case and then showing that if the statement is true for n, then it must also be true for n+1. In this case, the base case would be a = 0, and the inductive step would involve showing that if a + a = 0, then (a+1) + (a+1) = 0.

Are there any exceptions to this equation?

No, there are no exceptions to this equation. It holds true for all real numbers, including positive, negative, and zero. This can be seen by substituting any number for a in the equation and seeing that it still holds true.

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