- #1
bearhug
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Assuming that 71% of the Earth’s surface is covered with water at an average depth of 2.1 mi, estimate the mass of the water on the Earth in kilograms.
What I originally did for this problem was find the total surface area of the Earth to be 1.97e8 mi^2 and multiplied by 0.71 to get the water's surface area to be 1.40e8mi^2. Then I multiplied that to 2.1 mi to get volume and found mass using D= m/V and converting to kg. The answer I got was 1.22e15 kg and it's wrong. (This is done on a computer program). I'm not sure if my math is wrong or if I'm making it a lot more complicated than it really is.
Any help would be appreciated
What I originally did for this problem was find the total surface area of the Earth to be 1.97e8 mi^2 and multiplied by 0.71 to get the water's surface area to be 1.40e8mi^2. Then I multiplied that to 2.1 mi to get volume and found mass using D= m/V and converting to kg. The answer I got was 1.22e15 kg and it's wrong. (This is done on a computer program). I'm not sure if my math is wrong or if I'm making it a lot more complicated than it really is.
Any help would be appreciated