I to do a Fourier Sine Transform

In summary, the problem involves a function u(x,t) that satisfies the heat equation on the half line x≥0 for t>0, with K as a positive constant. The function has an initial condition of u(x,0)=cxe^(-x^2/4a^2) with c and a being constants, and boundary conditions of u(0,t)=0 and u(x,t) approaching 0 as x approaches infinity. The goal is to prove that the Fourier sine transform of u with respect to x is given by \hat{u}(s,t) = \hat{u}(s, 0)e^{-Kts^{2}} and to find the solution of the heat equation.
  • #1
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Homework Statement


A function u(x, t) satisfies the heat equation
[tex]K[/tex][tex]\frac{\delta^{2}u}{\delta x^{2}}[/tex] = [tex]\frac{\delta u}{\delta t}[/tex]
on the half line x [tex]\geq[/tex] 0 for t > 0, where [tex]K[/tex] is a positive constant. The initial
condition is
u(x, 0) = cxe[tex]^{\frac{-x^{2}}{4a^{2}}}[/tex]
with c and a being constants, and the boundary conditions are
u(0, t) = 0
u(x, t) [tex]\rightarrow[/tex] 0 as x [tex]\rightarrow[/tex] [tex]\infty[/tex]
Prove that the Fourier sine transform of u with respect to x is given by
[tex]\hat{u}[/tex](s,t) = [tex]\hat{u}[/tex](s, 0)e[tex]^{-Kts^{2}}[/tex]
Hence find the solution of the heat equation.

I have absolutely no idea what to do, and my books aren't helping at all. Anyone able to help me?
 
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  • #2
Homework Equations K\frac{\delta^{2}u}{\delta x^{2}} = \frac{\delta u}{\delta t}u(x, 0) = cxe^{\frac{-x^{2}}{4a^{2}}}u(0, t) = 0u(x, t) \rightarrow 0 as x \rightarrow \inftyThe Attempt at a SolutionI have no idea what to do.
 

FAQ: I to do a Fourier Sine Transform

What is a Fourier Sine Transform?

A Fourier Sine Transform is a mathematical operation that decomposes a function into its constituent sinusoidal components. It is used to analyze periodic or continuous signals, and is particularly useful in signal processing, image processing, and solving differential equations.

How does a Fourier Sine Transform work?

A Fourier Sine Transform works by breaking down a function into an infinite sum of sine functions with different frequencies and amplitudes. This allows us to examine the individual frequency components of the original function and see how they contribute to the overall signal.

What is the difference between a Fourier Sine Transform and a Fourier Transform?

The main difference between a Fourier Sine Transform and a Fourier Transform is that the former only deals with odd or sine components, while the latter deals with both even and odd or cosine and sine components. Additionally, the Fourier Transform is defined for both real and complex-valued functions, while the Fourier Sine Transform is only defined for real-valued functions.

What are some real-world applications of a Fourier Sine Transform?

The Fourier Sine Transform has many real-world applications, including image and sound processing, data compression, and solving differential equations in physics and engineering. It is also used in fields such as medical imaging, weather forecasting, and telecommunications.

Are there any limitations to using a Fourier Sine Transform?

Like any mathematical tool, there are limitations to using a Fourier Sine Transform. It is only applicable to functions that are periodic or continuous, and cannot be used for discontinuous or non-periodic signals. It also requires careful consideration of boundary conditions and the choice of frequency range to accurately analyze a signal.

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