I wrote the function y^50=x^2-5x-9.

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In summary, the conversation discusses a function and its inaccuracies in a graphing program. The function has two real roots and a large gap between the x-axis and the end of the curve. The gap is due to the inaccuracy of the program and the nature of the function around its zeros. The limit of the function as x approaches positive infinity is also mentioned and it is noted that the function should hit zero between its zeros on the x-axis. The conversation ends with a suggestion to consider the behavior of the function near its zeros.
  • #1
prasannapakkiam
I wrote the function y^50=x^2-5x-9. I found a large gap between the function from the x-axis to the end of the curve. My calculations show that the curve must touch the x-axis. Is this due to the accuracy of the program or does this curve indeed have a gap from the x-axis to the curve?
 
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  • #2
What is the limit of x^2-5x-9 as x goes to positive infinity?
 
  • #3
Well it tends to Infinity? But I don't see how that helps...
 
  • #4
aaaaaaaa I think there is a misunderstanding.

Okay the graph looks in a way like this like this:

______________________
/
|

--------------------------------x-axis


|
\________________________

the gap is on the left:smile:
 
  • #5
You mean there is a discontinuity?
 
  • #6
Yes I suppose you could call it that
 
  • #7
There is something wrong. There is a discontinuity, since x^2-5x-9 has real roots and hence an interval over which it is negative, but this discontinuity should be between the zeros, on the x-axis that is.
 
  • #8
hmm. So this is due clearly to the accuracy of the program?

As I thought that the range was: yER
 
  • #9
That's just an inaccuracy in the graphing program. The quadratic has 2 real roots, so the function hits zero, and both the quadratic and the fiftieth root function are continuous on their domains, so all the points in between appear as well.
 
  • #10
Thanks for the confirmation.
 
  • #11
Think about this prasannapakkiam, what happens to [tex]x^{\frac{1}{50}}[/tex] when x is close to zero but not exactly zero. Try some examples on your calculator, like 0.001^(1/50) for example.

Remember that your graphing program probably just chooses a bunch of points to evaluate and probably doesn't hit the zeros dead on. Can you see why [tex]x^2 - 5x -9[/tex] may be very close to zero but [tex](x^2 - 5x -9)^{\frac{1}{50}}[/tex] not necessarily so!

What I'm saying is this: Yes it is inaccuracy in the program that is causing the effect, but very much relevant to this is the nature of the function in question at points in the neighbourhood of it's zeros.
 
Last edited:

FAQ: I wrote the function y^50=x^2-5x-9.

What is the equation for y in terms of x?

The equation for y is y = ±√(x² - 5x - 9).

What is the value of y when x is equal to 0?

When x is equal to 0, the equation becomes y = ±√(-9) which equals ±3. Therefore, the value of y when x is equal to 0 is 3 or -3.

How many solutions does this equation have?

This equation has two solutions, one for each value of y (positive and negative) when solving for x.

What is the degree of this function?

The degree of this function is 50, as it is raised to the power of 50.

Can this equation be solved algebraically?

Yes, this equation can be solved algebraically by using the quadratic formula or by factoring.

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