*IBV6 Find vector eq of line passing thru (–1, 4),(3, –1). in form r = p + td

[karush]

Find a vector equation of the line passing through
$(–1, 4)$ and $(3, –1)$.
Give answer in the form \(\displaystyle r = p + td\),
where \(\displaystyle t \in {R}\)

position vector would be \(\displaystyle (3, -1) = p\)

direction vector would be (3+1,-1-4) = (4,-5) = d

so \(\displaystyle r=(3,-1)+t(4,-5)\)

 

[MarkFL]

Looks good! :D