- #1
karush
Gold Member
MHB
- 3,240
- 5
Find a vector equation of the line passing through
$(–1, 4)$ and $(3, –1)$.
Give answer in the form $$r = p + td$$,
where $$t \in {R}$$
position vector would be $$(3, -1) = p$$
direction vector would be (3+1,-1-4) = (4,-5) = d
so $$r=(3,-1)+t(4,-5)$$
$(–1, 4)$ and $(3, –1)$.
Give answer in the form $$r = p + td$$,
where $$t \in {R}$$
position vector would be $$(3, -1) = p$$
direction vector would be (3+1,-1-4) = (4,-5) = d
so $$r=(3,-1)+t(4,-5)$$
