- #1
henrco
- 47
- 2
Hi,
Could I please get some guidance on my approach and solution, for this particular problem.
Any assistance welcome.
1. Homework Statement
An ideal gas is compressed at a constant pressure of 1.3 atm from a volume of 20 L to 12 L. During this process it gives off 3.69 kJ of heat. What is the change in internal energy of this gas?
W=P.ΔV
Q = ΔU + W
Calculate the work done.
W = P.ΔV = 1.3 atm x (20 -12) L = 10.4 L atm
Convert to Joules = 10.4 x 101.3 = 1053.5 J
W = 1053.5 J
Q = ΔU + W
Given Q, calculate the change in internal energy.
ΔU = Q - W = 3.69 x 10^3 - 1053.5 = 2636.5 J
ΔU = 2636.5 J
Could I please get some guidance on my approach and solution, for this particular problem.
Any assistance welcome.
1. Homework Statement
An ideal gas is compressed at a constant pressure of 1.3 atm from a volume of 20 L to 12 L. During this process it gives off 3.69 kJ of heat. What is the change in internal energy of this gas?
Homework Equations
W=P.ΔV
Q = ΔU + W
The Attempt at a Solution
Calculate the work done.
W = P.ΔV = 1.3 atm x (20 -12) L = 10.4 L atm
Convert to Joules = 10.4 x 101.3 = 1053.5 J
W = 1053.5 J
Q = ΔU + W
Given Q, calculate the change in internal energy.
ΔU = Q - W = 3.69 x 10^3 - 1053.5 = 2636.5 J
ΔU = 2636.5 J