Ideal op amp (current to voltage converter + inverting)

In summary, the question is asking for an expression relating the output voltage to the input current in a circuit with a second opamp. The attempted solution includes the input voltage and resistors, but does not include RL. However, if the opamp's output can drive RL, then it does not need to be included in the gain equation. In real life, one would still need to check the opamp's output current capability and voltage swing.
  • #1
naspek
181
0

Homework Statement



Hey there.. need helps here..
The question is..
Derive an expression relating the output voltage, Vo to the input current, Iin.

The Attempt at a Solution



i try to derive it.. but..
got problem with RL
V1 = -IinRf
Vo =- R2/R1(-IinRf) how to include Rl in my derivation?

currenttovoltageconverter.jpg
 
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  • #2
naspek said:

Homework Statement



Hey there.. need helps here..
The question is..
Derive an expression relating the output voltage, Vo to the input current, Iin.

The Attempt at a Solution



i try to derive it.. but..
got problem with RL
V1 = -IinRf
Vo =- R2/R1(-IinRf) how to include Rl in my derivation?

currenttovoltageconverter.jpg

Good question. As long as the 2nd opamp's output is capable of driving RL, you don't need to include it in the gain equation. In real life, you would check the output current capability of the opamp, figure out the voltage swing based on your gain equation (for whatever values of Iin you expect), and make sure you weren't exceeding that output current rating.
 

FAQ: Ideal op amp (current to voltage converter + inverting)

What is an ideal op amp?

An ideal op amp, short for operational amplifier, is a type of electronic circuit component that is designed to amplify and process signals. It has two input terminals, a non-inverting terminal (+) and an inverting terminal (-), and one output terminal. In an ideal op amp, the input impedance is infinite, the output impedance is zero, and it has infinite gain and bandwidth.

What is a current to voltage converter?

A current to voltage converter is a circuit that converts an input current signal into an output voltage signal. It typically consists of a resistor and an op amp, with the input current flowing through the resistor and creating a voltage drop that is amplified by the op amp. This type of converter is commonly used in electronic applications such as sensor signal conditioning and current sensing.

How does an inverting op amp work?

In an inverting op amp configuration, the input signal is applied to the inverting terminal (-) of the op amp, while the non-inverting terminal (+) is connected to ground or a reference voltage. The output voltage is then the amplified and inverted version of the input voltage, with the amount of amplification determined by the ratio of the feedback resistor to the input resistor.

What are the advantages of using an ideal op amp in a current to voltage converter?

Using an ideal op amp in a current to voltage converter offers several advantages. Firstly, it provides a high input impedance, which minimizes the loading effect on the input signal. Secondly, it has a low output impedance, allowing it to easily drive loads without causing significant voltage drops. Finally, an ideal op amp has a very high gain, allowing for precise and accurate signal amplification.

What are some common applications of an ideal op amp current to voltage converter?

An ideal op amp current to voltage converter is commonly used in electronic circuits for various applications. Some examples include current sensing in power supplies, signal conditioning for sensors, and audio amplification. It can also be used in instrumentation, such as oscilloscopes and data acquisition systems, to accurately measure and amplify small signals.

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