- #1
s3a
- 818
- 8
Homework Statement
The problem and its solution are attached as "IEEE754_ProblemAndSolution.jpg".
Homework Equations
The 32-bit/single-precision IEEE 754 procedure.
The Attempt at a Solution
1) What is the reasoning behind the log|-8.573 × 10^13| / log(2) computation?
2) When obtaining the exponent 47 in 2^47 from the computation in my question #1, I noticed that a 2^47 / 1.4074 × 10^14 = 1 was multiplied with -8.573 × 10^13.
My question for this part #2 is: why was that 47 “hunted down”? Why couldn't I have multiplied -8.573 × 10^13 by 2^50 / 1.1259 × 10^15 = 1 for example? Is there a significance to this or could I have chosen to multiply by 2^46 / 7.034 × 10^13 as well?
3) For the number of significant bits, I get the 14 – 1 part but, I don't understand how the 4/log(2) computation was obtained.
If something is unclear with what I am asking, tell me and I will attempt to clarify the situation.
Any input would be greatly appreciated!