- #1
bjersey
- 5
- 0
I'm having issues proving the following which should be simple:
If A and B are mutually exclusive, prove Pr(A) <= Pr(B')
From the statement about being mutually exclusive, I know A [tex]\cap[/tex] B = [tex]\phi[/tex]
Therefore we have P(A [tex]\cap[/tex] B) = Pr(A) + Pr(B)
Also, A = A [tex]\cap[/tex] B'
and B = A' [tex]\cap[/tex] B
But I'm having a hard time putting all of this together.
Please help. Thanks.
If A and B are mutually exclusive, prove Pr(A) <= Pr(B')
From the statement about being mutually exclusive, I know A [tex]\cap[/tex] B = [tex]\phi[/tex]
Therefore we have P(A [tex]\cap[/tex] B) = Pr(A) + Pr(B)
Also, A = A [tex]\cap[/tex] B'
and B = A' [tex]\cap[/tex] B
But I'm having a hard time putting all of this together.
Please help. Thanks.