- #1
k8e591
- 2
- 0
If vector A=10i+49j, and vector B=vector A/2, then does vector B=1/2(10i+49j)?
k8e591 said:If vector A=10i+49j, and vector B=vector A/2, then does vector B=1/2(10i+49j)?
The magnitude of vector B can be calculated using the formula: |B| = √(Bx² + By²), where Bx and By are the components of vector B. In this case, the magnitude of vector B is approximately 24.5.
The direction of vector B can be determined by finding the angle it makes with the positive x-axis. In this case, the direction of vector B is approximately 78.7 degrees from the positive x-axis.
Vector B is half the magnitude of vector A. This is because vector B is calculated by dividing vector A by 2, which means that the magnitude of vector B is half of the magnitude of vector A.
Yes, vector B is parallel to vector A. This is because both vectors have the same direction (78.7 degrees from the positive x-axis) and their magnitudes are directly proportional (B = A/2).
Yes, vector B can be written in terms of unit vectors. The unit vector in the direction of vector B can be calculated by dividing vector B by its magnitude. So, vector B can be written as B = 0.408i + 0.917j.