Image of x+y=1 under f(z) = z^2

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In summary, the "Image" of x+y=1 under f(z) = z^2 represents the set of all complex numbers that result from plugging in x+y=1 into the function f(z) = z^2. To find the image, you can simply plug in the input and simplify the resulting expression. The significance of the image is that it helps us visualize how the function transforms the input to the output. The image is unique for any given input, and it can be a complex number since the function operates on complex numbers.
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complexnumber
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For f(z) = z^2 find the image of x + y = 1

f(z) = z^2 = (x + iy)^2 = x^2 + 2ixy - y^2

u(x,y) = x^2 - y^2
v(x,y) = 2xy
 
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  • #2
Here's how I would approach this problem. Every point on the line has coordinates (in the complex plane) of (x, 1 - x). A point on this line can be represented as z = x + i(1 - x). What does your function f do to these complex numbers?
 

FAQ: Image of x+y=1 under f(z) = z^2

What is the "Image" of x+y=1 under f(z) = z^2?

The image of x+y=1 under f(z) = z^2 refers to the set of all complex numbers that result from plugging in x+y=1 into the function f(z) = z^2.

How do you find the image of x+y=1 under f(z) = z^2?

To find the image of x+y=1 under f(z) = z^2, you can simply plug in x+y=1 into the function and simplify the resulting expression.

What is the significance of the "Image" of x+y=1 under f(z) = z^2?

The image of x+y=1 under f(z) = z^2 is significant because it represents the output or result of the function for a specific input. It helps us visualize how the function transforms or maps the input to the output.

Is the "Image" of x+y=1 under f(z) = z^2 unique?

Yes, the image of x+y=1 under f(z) = z^2 is unique. This means that for any given input, there can only be one output or image.

Can the "Image" of x+y=1 under f(z) = z^2 be a complex number?

Yes, the image of x+y=1 under f(z) = z^2 can be a complex number, as the function f(z) = z^2 operates on complex numbers. This means that the resulting image can also be a complex number.

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