- #1
complexnumber
- 62
- 0
For f(z) = z^2 find the image of x + y = 1
f(z) = z^2 = (x + iy)^2 = x^2 + 2ixy - y^2
u(x,y) = x^2 - y^2
v(x,y) = 2xy
f(z) = z^2 = (x + iy)^2 = x^2 + 2ixy - y^2
u(x,y) = x^2 - y^2
v(x,y) = 2xy