Impedance and Frequency- directly or indirectly related?

[Dunkaroos]

Impedance and Frequency- directly or indirectly related?


I think it's inversely. Am I correct?
Let Impedance =Z
p==pressure
v=velocity

Z = p/v and v=f(lamda)

So Z= p / (f(lamda))

Isn't Impedance inversely proportional to frequency?

 

[berkeman]

Yeah, I was totally confused by your initial thread:

https://www.physicsforums.com/showthread.php?t=134718

In general, we discourage double-posting here on the PF, but we'll let you get away with it this time if you DEFINE WHAT THE HECK YOU MEAN BY IMPEDANCE. Is it the characteristic impedance for a freely propagating EM wave, or some quantity for a physical tension wave propagating on a string or what?

You need to be more specific in your problem statement. Please.

 

[kyle8921]

Yes, you are correct. Impedance and frequency are indirectly related. This means that as one increases, the other decreases. In this case, impedance is inversely proportional to frequency. As frequency increases, impedance decreases and vice versa. This relationship can be seen in the equation Z = p / (f * λ), where frequency is in the denominator. This shows that as frequency increases, impedance decreases. This relationship is important in understanding the behavior of electrical circuits and acoustic systems, where impedance and frequency play crucial roles.