- #1
EEstudentNAU
- 30
- 0
I am asked to implment an address decoder for the 68k with the following units: 4MB of eeprom using 512k*8 chips, 1 MB of RAM using 128k*8 chips, 4MB of DRAM using 512k*4 chips, and 128 bytes of i/o space.
I do not understand the question very well, and any help would be appreciated.
I do not understand the question very well, and any help would be appreciated.