- #1
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I found (nitpicking, I agree -- but that's what ##\TeX## does to you 
)$$
{dr\over dt} = {dr\over d\phi}{d\phi\over dt}$$ looking ugly and want to lift the two dr . However,
{dr\over dt} = {\vphantom {\phi} dr\over d\phi}{d\phi\over dt} didn't deliver as I expect:
$$
{\vphantom {\phi dr } dr\over dt} = {\vphantom {\phi} dr\over d\phi}{d\phi\over dt}$$ where omitting the \vphantom does take care of the lifting :
$$
{ dr\over dt} = {{\phi} \ dr\over d\phi}{d\phi\over dt}$$ (but I of course don't want the ##\phi##)
anyone have a tip how to get this done ?
PS the ordinary \phantom does work as I expect -- vertically as well as horizontally:
$$
{\phantom {\phi } dr\over dt} = {\phantom {\phi} dr\over d\phi}{d\phi\over dt}$$
)$${dr\over dt} = {dr\over d\phi}{d\phi\over dt}$$ looking ugly and want to lift the two dr . However,
{dr\over dt} = {\vphantom {\phi} dr\over d\phi}{d\phi\over dt} didn't deliver as I expect:
$$
{\vphantom {\phi dr } dr\over dt} = {\vphantom {\phi} dr\over d\phi}{d\phi\over dt}$$ where omitting the \vphantom does take care of the lifting :
$$
{ dr\over dt} = {{\phi} \ dr\over d\phi}{d\phi\over dt}$$ (but I of course don't want the ##\phi##)
anyone have a tip how to get this done ?
PS the ordinary \phantom does work as I expect -- vertically as well as horizontally:
$$
{\phantom {\phi } dr\over dt} = {\phantom {\phi} dr\over d\phi}{d\phi\over dt}$$
