- #1
Dan350
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I think I almost got this problem would you review or correct me please?:
A spring with a spring constant k=34/Nm is attached to a block of mass M1=1.5kg. Initially that block is at rest on a friction less surface. A second block, M2, of mass of 4.5kg is moving with speed v= 5.5m/s toward the first block. When the second block hits the first block, the two blocks slide together to the left, compressing the spring, and then rebound for a half cycle of harmonic motion.
You can see an image below*
a) With what speed does M2 leave M1 after the half cycle of oscillation?
b) What time is takes for the half period of simple harmonic motion during which the block are in contact?
c)What is the maximum compression of the spring
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Relevant Equations
Pi=Pf
Δp=FΔt
K+PE=ΔU
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My attempt
a)
Half cycle of oscillation is at the moment the spring is at its eqilibriuim after the collision( that's what i think)
for a I used conservation of momentum ∴ P1=Pf
so my attempt: m2Vi=(m1+m2)vf
where vi= initial velocity and vf= final velocity
Solving for vf i get 4.125
b)
Since the momentum is going both negative and positive durin the half cycle
Δp=fΔt
-p-p=fΔt
-2(m1+m2)vf=-kxt
solving for t i got 84 seconds
c) the x from above I got it from here;
1/2(m1+m2)vf^2=1/2(kx^2)
solving for x i got 1.73m
Any corrections?
Thank you in advance
Cheers
-Daniel