- #1
Leoragon
- 43
- 0
First of all, I'm 13 so I might not comprehend the complex vocabulary or symbols others might use. Second, I just joined!
Okay, let's get to it.
I think I know what the inverse square law is: if a number goes up by x, then the other number is the square of x but in the negative side. Right?
I also think that the force of gravity on a 1kg object on the surface of the Earth (from the average radius) is 9,818,373.084 N . Now what if the distance gets increased by 10 metres? In the equation for the force: F=Gm1m2/r2, do you just add 10 to the r? So it would equal 9,787,623.422 N?
1st equation)
F = 9,818,373.084 N
G = 6.673 X 10-11
m1= 1kg
m2= 5.97219 X 1024 (Earth)
r2 = 40,589,641 (63712)
2nd equation)
F = 9,787,623.422 N
G = 6.673 X 10-11
m1 = 1kg
m2 = 5.97219 X 1024 (Earth)
r2 = 40,717,161 (63812)
If so, where does the inverse square law go?
And is this correct?
Okay, let's get to it.
I think I know what the inverse square law is: if a number goes up by x, then the other number is the square of x but in the negative side. Right?
I also think that the force of gravity on a 1kg object on the surface of the Earth (from the average radius) is 9,818,373.084 N . Now what if the distance gets increased by 10 metres? In the equation for the force: F=Gm1m2/r2, do you just add 10 to the r? So it would equal 9,787,623.422 N?
1st equation)
F = 9,818,373.084 N
G = 6.673 X 10-11
m1= 1kg
m2= 5.97219 X 1024 (Earth)
r2 = 40,589,641 (63712)
2nd equation)
F = 9,787,623.422 N
G = 6.673 X 10-11
m1 = 1kg
m2 = 5.97219 X 1024 (Earth)
r2 = 40,717,161 (63812)
If so, where does the inverse square law go?
And is this correct?