- #1
Brilliant
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Hi, I missed a few days of my calculus class. I've managed to figure out how to use substitution to solve an indefinite integral, and can apply the log properties to some extent. I just can't figure out this problem.
Find the indefinite integral:
[tex]\int{\frac{1}{x ln(x^3)}}dx[/tex]
2. The attempt at a solution
Well, since d/dx ln(x) is u'/u I know something is kinda wack with the bottom. I first tried to substitute with u=x^3, but then du is 3x^2 and there is only x on the bottom not x squared. I then thought it might be backwards, since the x on bottom is like x^-1 and it would have an integral with a natural log in it, but that wasn't really working out either.
I'm pretty stumped, I've attempted it several times.
Thanks for your help!
Homework Statement
Find the indefinite integral:
[tex]\int{\frac{1}{x ln(x^3)}}dx[/tex]
2. The attempt at a solution
Well, since d/dx ln(x) is u'/u I know something is kinda wack with the bottom. I first tried to substitute with u=x^3, but then du is 3x^2 and there is only x on the bottom not x squared. I then thought it might be backwards, since the x on bottom is like x^-1 and it would have an integral with a natural log in it, but that wasn't really working out either.
I'm pretty stumped, I've attempted it several times.
Thanks for your help!