- #1
Kaguro
- 221
- 57
- Homework Statement
- In a parallel plate capacitor the distance between the plates is 10cm. 2 dielectric slabs of thickness 5 cm each and dielectric constants 2 and 4 respectively are inserted between the plates. A potential difference of 10V is applied between the plates. Find the net bound charge density at the interface of the two dielectrics.
- Relevant Equations
- E0=V/d
E=E0/k
Gauss' Law
E0=V/d = 100/0.1 =1000v/m
In slab 1, E1=E0/k1=500v/m
In slab 2, E2=E0/k2=250v/m
Applying Gauss' Law to a box surface surrounding the interface with area equal to the plates we have
(-E1+E2)*A = Q/epsilon_naught
So charge density sigma = -250 epsilon_naught
But answer given is (-2000/3)*epsilon_naught
What did i do wrong?
In slab 1, E1=E0/k1=500v/m
In slab 2, E2=E0/k2=250v/m
Applying Gauss' Law to a box surface surrounding the interface with area equal to the plates we have
(-E1+E2)*A = Q/epsilon_naught
So charge density sigma = -250 epsilon_naught
But answer given is (-2000/3)*epsilon_naught
What did i do wrong?