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Punchlinegirl
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A 5.97 m long steel beam is accidentally dropped by a construction crane from a height of 6.82 m. The horizontal component of the Earth's magnetic field over the region is 12.2 [tex]\mu T[/tex]. The acceleration of gravity is 9.8 m/s^2. What is the induced emf in the beam just before impact with the Earth, assuming its long dimension remains in a horizontal plane, oriented perpendicularly to the horizontal component of the Earth's magnetic field? Answer in units of mV.
I know that E= change in flux/change in time
To get the change in time I used the equation
x(t)= x_o +v_o*t +.5 gt^2
where x_o=v_o=0
and x(t)= 6.82 m.
solving for t gave me .834 s.
Then for the flux I think it's just B*L= 72.8... but I don't think that's right...
Can someone please help me?
I know that E= change in flux/change in time
To get the change in time I used the equation
x(t)= x_o +v_o*t +.5 gt^2
where x_o=v_o=0
and x(t)= 6.82 m.
solving for t gave me .834 s.
Then for the flux I think it's just B*L= 72.8... but I don't think that's right...
Can someone please help me?