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pierretong
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Homework Statement
A solenoid is wound with a single layer of insulated copper wire of diameter 2.100 mm and has a diameter of 3.000 cm and is 1.900 m long. Assume that adjacent wires touch and that insulation thickness is negligible.
a) How many turns are on the solenoid?
Solved: determined to be 904
b)What is the inductance per meter (H/m) for the solenoid near its center?
Homework Equations
Inductance = (constant mu0)* (N^2)*A / l
mu0 = 4*PI*10^-7
N = 904 turns
A = PI*R^2 (R = 2.100 mm/2)
l = length of solenoid = 1.900 m
The Attempt at a Solution
Plugged all those variables above (converted R to meters) and got 0.00019 for the inductance.
I don't understand what it means to find the Inductance per Meter at the center of the solenoid? Do I have to divide by 1.900 m again? Confused as to what I'm supposed to do.