- #1
dilectron
- 5
- 1
Hi,
I have a toroid of a soft magnetic material (any). I wind the complete toroid with single turn coils and connect all their terminals in parallel. Then I wind a second layer of single turn coils on the previous layer and so on.
I want to calculate the equivalent inductance L. I calculate it for a vacuum core (Kappa vac or µ0) and can multiply my end result with the relative permeability (µr).
So I first calculated the self-inductances of the single coils, then I use these self-inductances to calculate the mutual inductance of coils that lay on top of each other with M=k SQRT(Lx*Ly) and used a value of 1 for k since normally coils on top of each other are considered to have perfect coupling. Then with Le=(L1*L2)-M² / L1+L2 - 2M i calculated the inductance of EACH SET of 2 coils in such pancake stack. This yields almost always zero (or numbers E-19 and smaller) because Lx and Ly (given moderated stack of 5 layers with thin wire) are almost identical. So, no matter how many layers I have on top of each other, the equivalent inductance is L, the inductance of one coil of one turn.
Now I consider such a parallel pancake stack as a single coil, and my toroid is filled completely with them so that I have the maximum possible pancakes on it. This keeps their mutual angles and inter-distance short and the k value for a toroid is always one (perfect coupling).
So we have again a situation of perfectly coupling, identical coils in an aiding configuration. So technically, here also the inductance L should be the L of one single pancake since Lx*Ly will again be equal to M². Until here my conclusion was that the inductance L for such toroidal core filled with parallel pancake coils is the L of one single turn of coil. As a result the inductive reactance (XL) will be very low and the ohmic resistance (R in parallel) will be very low too.
Let's call this a short-circuit coil configuration.
Since the above approach is relatively heavy I started to look for better and faster ways to calculate the total L of a toroid with only single turn parallel windings.
I found Grover's, "Tables for the Calculation of the inductance of circular coils of rectangular cross section." and I used formula 4 (for pancake coils: L=0.001 N² a P f) and used the tables in the book to make the corrections the way the book explains.
I also made the calculation with (µ0N²h/2π)*ln(b/a) (from MIT http://web.mit.edu/viz/EM/visualizations/notes/modules/guide11.pdf).
In both cases I get a result for L that is 3 to 4 orders of magnitude LOWER then the calculation for the pancakes above. However, if I use the total number of turns (as if the toroid with all pancakes was a single coil) then my end total is 2 orders of magnitude bigger then a single turn of coil. I did take into account that the formula from Grover uses centimeters and yield micro Henry and that the one for MIT is in SI units. So the only explanation I can see so far is that the N² makes the difference since in the approach via individual pancakes N=1, hence 1² = 1, and is neutral in multiplication.
So my question is, does the type of formulas as mentioned in the previous paragraph (Grover & MIT) apply if all the turns are actually in parallel.
Those books say nothing about that and the formula's don't give it away either. One could think that for inductance calculation it isn't important whether you use a single coil of X horizontal turns and y vertical layers high OR one of X times 1 horizontal turn and Y times 1 vertical layer high connected in parallel, because all dimensions remain the same and the total number of turns remains the same. At best the current distribution (if we see the rectangular winding as a current sheet) would be better with the parallel version.
Can someone help me to clarify what approach is the best and possible explain why.
Thanks.
I have a toroid of a soft magnetic material (any). I wind the complete toroid with single turn coils and connect all their terminals in parallel. Then I wind a second layer of single turn coils on the previous layer and so on.
I want to calculate the equivalent inductance L. I calculate it for a vacuum core (Kappa vac or µ0) and can multiply my end result with the relative permeability (µr).
So I first calculated the self-inductances of the single coils, then I use these self-inductances to calculate the mutual inductance of coils that lay on top of each other with M=k SQRT(Lx*Ly) and used a value of 1 for k since normally coils on top of each other are considered to have perfect coupling. Then with Le=(L1*L2)-M² / L1+L2 - 2M i calculated the inductance of EACH SET of 2 coils in such pancake stack. This yields almost always zero (or numbers E-19 and smaller) because Lx and Ly (given moderated stack of 5 layers with thin wire) are almost identical. So, no matter how many layers I have on top of each other, the equivalent inductance is L, the inductance of one coil of one turn.
Now I consider such a parallel pancake stack as a single coil, and my toroid is filled completely with them so that I have the maximum possible pancakes on it. This keeps their mutual angles and inter-distance short and the k value for a toroid is always one (perfect coupling).
So we have again a situation of perfectly coupling, identical coils in an aiding configuration. So technically, here also the inductance L should be the L of one single pancake since Lx*Ly will again be equal to M². Until here my conclusion was that the inductance L for such toroidal core filled with parallel pancake coils is the L of one single turn of coil. As a result the inductive reactance (XL) will be very low and the ohmic resistance (R in parallel) will be very low too.
Let's call this a short-circuit coil configuration.
Since the above approach is relatively heavy I started to look for better and faster ways to calculate the total L of a toroid with only single turn parallel windings.
I found Grover's, "Tables for the Calculation of the inductance of circular coils of rectangular cross section." and I used formula 4 (for pancake coils: L=0.001 N² a P f) and used the tables in the book to make the corrections the way the book explains.
I also made the calculation with (µ0N²h/2π)*ln(b/a) (from MIT http://web.mit.edu/viz/EM/visualizations/notes/modules/guide11.pdf).
In both cases I get a result for L that is 3 to 4 orders of magnitude LOWER then the calculation for the pancakes above. However, if I use the total number of turns (as if the toroid with all pancakes was a single coil) then my end total is 2 orders of magnitude bigger then a single turn of coil. I did take into account that the formula from Grover uses centimeters and yield micro Henry and that the one for MIT is in SI units. So the only explanation I can see so far is that the N² makes the difference since in the approach via individual pancakes N=1, hence 1² = 1, and is neutral in multiplication.
So my question is, does the type of formulas as mentioned in the previous paragraph (Grover & MIT) apply if all the turns are actually in parallel.
Those books say nothing about that and the formula's don't give it away either. One could think that for inductance calculation it isn't important whether you use a single coil of X horizontal turns and y vertical layers high OR one of X times 1 horizontal turn and Y times 1 vertical layer high connected in parallel, because all dimensions remain the same and the total number of turns remains the same. At best the current distribution (if we see the rectangular winding as a current sheet) would be better with the parallel version.
Can someone help me to clarify what approach is the best and possible explain why.
Thanks.
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