Inductor as a differentiator (op amp)

In summary, the conversation discusses a circuit involving an op amp, a time varying voltage source, a resistor, and an inductor. The OP is trying to determine if this configuration is a differentiator and has attempted to use nodal equations to solve for the current. However, there seems to be confusion about the use of an inductor and whether this circuit would act as an integrator instead.
  • #1
jesuslovesu
198
0

Homework Statement


Sorry this computer doesn't have access to PSPICE and I don't have a scanner, but let's say that I have an op amp.
1) there is a time varying voltage source Vs
2) There is a resistor R1 connected to the inverting input of the op amp
3) The noninverting pin is connected to ground
4) There is an inductor connected from the inverting pin to the output of the op amp where there is also + - Vout represented.

How does one do the nodal equations to verify that this configuration is a differentiator?

Homework Equations





The Attempt at a Solution



I came up with (0 - Vs) / R + i(t) = 0
Vs / R = i(t)
I know vL = L di/dt
but wouldn't that be an integrator if I wanted to solve for i?

I don't see how this would be a differentiator
 
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  • #2
jesuslovesu said:
I came up with (0 - Vs) / R + i(t) = 0
That can't be right. There is no L in that equation.
 

FAQ: Inductor as a differentiator (op amp)

What is an inductor as a differentiator in an op amp?

An inductor as a differentiator in an op amp is a circuit arrangement that uses an inductor and a capacitor to create a high-pass filter. This allows for the differentiation of an input signal, meaning that the output signal will be proportional to the rate of change of the input signal.

How does an inductor as a differentiator work?

An inductor as a differentiator works by using the inductor's ability to resist changes in current flow and the capacitor's ability to store and release charge. When an input signal is applied to the circuit, the inductor resists the change in current, causing a voltage drop across it. This voltage drop is then amplified by the op amp and passed through the capacitor, resulting in a differentiated output signal.

What are the advantages of using an inductor as a differentiator?

One advantage of using an inductor as a differentiator is that it allows for the amplification of high-frequency signals, making it useful in applications such as audio amplifiers. Additionally, it has a simple, low-cost design and can be easily integrated into other circuits.

What are the limitations of using an inductor as a differentiator?

One limitation of using an inductor as a differentiator is that it requires careful selection of the inductor and capacitor values to achieve the desired frequency response. It also has a limited frequency range and may not be suitable for low-frequency signals. Additionally, inductors can be susceptible to noise and variations in temperature.

How is an inductor as a differentiator different from other filter circuits?

An inductor as a differentiator is different from other filter circuits, such as RC or RLC circuits, in that it only allows for the differentiation of an input signal, rather than filtering out specific frequencies. It also has a different frequency response and may be more suitable for certain applications, such as audio amplifiers. Additionally, its design and component values may differ from other filter circuits.

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