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phys1618
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Homework Statement
One way to measure the muzzle velocity of a bullet is to fire it horizontally inot a massive block of wood hanging from a string an d measure the height to which the wood (containing the bullet) rises.
in one experiment the bullet had a mass of .05kg, and the wood has a mass of 2kg. After the shot, the wood and bullet rose to a height of .5 meteres. waht was the original speed of the bullet?
Homework Equations
d=(vf2-vi2)/2a
KE=1/2Mv2
change of ENERGYsystem=constant
PEi +KEi=PEf + KEf
PE=Mgh
The Attempt at a Solution
i ended up with 29.17 m/s for the original speed