Inelastic collision followed by circular motion

AI Thread Summary
After the inelastic collision, the masses travel at a speed of 2.25 m/s. The discussion explores the subsequent motion of these masses on a circular track. Three distinct possibilities for their behavior are proposed, although not explicitly listed in the thread. The focus remains on understanding the dynamics following the collision and the implications for circular motion. Further clarification on these possibilities is sought to deepen the analysis.
Sal Coombs
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Homework Statement
A 3.0-kg mass is sliding on a horizontal frictionless surface with a speed of 3.0 m/s when it collides with a 1.0-kg mass initially at the bottom of a circular track. The masses stick together and slide up a frictionless circular track of radius 0.40 m. To what maximum height, h, above the horizontal surface (the original height of the masses) will the masses slide?
Relevant Equations
mv = mv Momentum
1/2mv^2 Kinetic Energy
mgh Potential Energy
(mv^2)/r Centripetal Force
Found the speed at which the masses will travel after their collision: 2.25m/s
Not sure what to do next...
 
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Sal Coombs said:
Found the speed at which the masses will travel after their collision: 2.25m/s
Not sure what to do next...
What happens when the masses follow the circular track?
 
To expand on @PeroK's question, there are three distinct possibilities. Can you list them?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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