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girl52
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inelastic collision...kinetic energy lost?
a bullet with a mass of 6 g is fired through a 1.25kg block of wood on a frictionless surface. initial speed of the bullet is 896 m/s and speed of bullet after it passes through it is 435 m/s. what's the final velocity? how much KE is lost?
ke lost=ke initial-ke final
ke lost=1/2mvf-1/2mvi
i got 11.2 m/s for the final velocity of the wood
KEi=1/2(.006)(896^2) + 0
KEf=1/2(.006)(435^2) + 1/2(1.25)(11.225^2)
i got 2408.228 - 488.925
thats not negative..where did i go wrong??
Homework Statement
a bullet with a mass of 6 g is fired through a 1.25kg block of wood on a frictionless surface. initial speed of the bullet is 896 m/s and speed of bullet after it passes through it is 435 m/s. what's the final velocity? how much KE is lost?
Homework Equations
ke lost=ke initial-ke final
ke lost=1/2mvf-1/2mvi
i got 11.2 m/s for the final velocity of the wood
The Attempt at a Solution
KEi=1/2(.006)(896^2) + 0
KEf=1/2(.006)(435^2) + 1/2(1.25)(11.225^2)
i got 2408.228 - 488.925
thats not negative..where did i go wrong??
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