- #1
uliuli
- 2
- 0
Hi everyone,
I was thinking about the relationship between angular velocity and angular momentum for a rigid body: [itex]I \omega = L[/itex]. In particular, I'm trying to gain a little bit of intuition as to what transformations [itex]I[/itex] can perform on [itex]\omega[/itex].
Let's use a reference frame at the center of mass of the body. We can rewrite the inertia tensor as: [itex]I = R I_0 R^T[/itex], where [itex]I_0[/itex] is the diagonalized inertia tensor and [itex]R[/itex] rotates the coordinate system from a principle-axes-aligned frame to the current frame. When I now apply [itex]I[/itex] to [itex]\omega[/itex], I am equivalently rotating [itex]\omega[/itex] by some arbitrary rotation, scaling each component by a positive (and in general, different for each component) number, and rotating by the inverse of the first rotation. In general, what does this concatenation of transformations give me?
Thanks!
I was thinking about the relationship between angular velocity and angular momentum for a rigid body: [itex]I \omega = L[/itex]. In particular, I'm trying to gain a little bit of intuition as to what transformations [itex]I[/itex] can perform on [itex]\omega[/itex].
Let's use a reference frame at the center of mass of the body. We can rewrite the inertia tensor as: [itex]I = R I_0 R^T[/itex], where [itex]I_0[/itex] is the diagonalized inertia tensor and [itex]R[/itex] rotates the coordinate system from a principle-axes-aligned frame to the current frame. When I now apply [itex]I[/itex] to [itex]\omega[/itex], I am equivalently rotating [itex]\omega[/itex] by some arbitrary rotation, scaling each component by a positive (and in general, different for each component) number, and rotating by the inverse of the first rotation. In general, what does this concatenation of transformations give me?
Thanks!