- #1
S_fabris
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This is one of many postings from me this week unfortunately I'm just not getting the correct answers...anyway here I go :
A toy balloon is inflated with helium at a constant pressure that is 4.2e5 Pa in excess of atmospheric pressure. If the balloon inflates from a volume of 1.4e-4m3 to 9.6e-4m3, how much work is done by the balloon on the surrounding air? answer in J
this is my work
P= 4.2e5Pa + 101300Pa
= 521 300 Pa
dV = (Vf-Vi) = (9.6e-4 - 1.4e-4)
= 0.00082m3
W= 521 300Pa x (0.00082m3)
427.466 J (incorrect on homework server)
I'm guessing it has something to do with the work on the surrounding air...I have been looking in my books and course notes for this and I can't find anything...can anybody help me out??
Any help is appreciated,
Sergio
A toy balloon is inflated with helium at a constant pressure that is 4.2e5 Pa in excess of atmospheric pressure. If the balloon inflates from a volume of 1.4e-4m3 to 9.6e-4m3, how much work is done by the balloon on the surrounding air? answer in J
this is my work
P= 4.2e5Pa + 101300Pa
= 521 300 Pa
dV = (Vf-Vi) = (9.6e-4 - 1.4e-4)
= 0.00082m3
W= 521 300Pa x (0.00082m3)
427.466 J (incorrect on homework server)
I'm guessing it has something to do with the work on the surrounding air...I have been looking in my books and course notes for this and I can't find anything...can anybody help me out??
Any help is appreciated,
Sergio