- #1
azserendipity
- 10
- 0
Homework Statement
I understand how to do initial value problems but I'm slightly stuck when the initial values are y(0) = y'(0)=0
The question is Solve:
y''+3y''+2y=f(t), y(0)=y'(0)=0 where f(t) is a square wave.
Homework Equations
[itex]\Im[/itex]{y'} =s[itex]\Im[/itex]{y}-y(0)
[itex]\Im[/itex]{y''}=s[itex]^{2}[/itex][itex]\Im[/itex]-sy'(0)-y'(0)
The Attempt at a Solution
I've gotten so far:
(s[itex]^{2}[/itex][itex]\Im[/itex](y)-sy(0)-y'(0))+3(s[itex]\Im[/itex](y)-y(0))+2[itex]\Im[/itex](y)=F(t)
[itex]\Rightarrow[/itex] (s[itex]^{2}[/itex]-y'(0)-0)+3s-y'(0)+2=F(t)
Its then when I substitute in the initial condition I get
s[itex]^{2}[/itex]+3s+2=F(t)
I'm not sure this is right because I can't then do partial fractions or the inverse of it to get the final answer.
The other thing is I don't understand how F(t) being a square wave affects it.
Any help would be greatly appreciated!