Inrush current in a transformer chain

In summary, inrush current in a transformer chain refers to the high initial current that flows when a transformer is first energized. This phenomenon occurs due to the sudden application of voltage, which magnetizes the core and can lead to a peak current several times greater than the normal operating current. The inrush current is influenced by factors such as the transformer's core material, design, and the phase of the supply voltage at the moment of energization. Understanding inrush current is crucial for designing protection systems and ensuring the reliability of transformer operations.
  • #1
Guineafowl
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How does connecting two transformers in a chain affect the inrush current (at switch-on), as opposed to one transformer on its own?
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This is the proposal, except the two middle voltages are 110V, not 12V.

Say the max switch-on inrush current of XFMR1 is xA with the secondary open, would the value change significantly in the above arrangement, with the secondary of XFMR2 open?
 
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  • #2
You have twice the leakage inductance, so the inrush may be a little lower.
 
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  • #3
berkeman said:
You have twice the leakage inductance, so the inrush may be a little lower.
Thanks.
 
  • #4
Hard to answer without knowing what causes the inrush current.

- If it's from the load circuitry, the I'm with @berkeman, more series impedance buffer means less inrush magnitude, but longer duration (probably).

- If it's from the transformer core saturation because of residual magnetization, then it's just not predictable, at least to me. But, the same or maybe more.

- If it's from winding capacitance then you get an addition of some sort. Complicated by turns ratio and leakage inductance.

The short answer is that you need a much more detailed model, which is pretty difficult. As you drew it, I'd say there's no inrush surge in any case.
 
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  • #5
If the magnetic core was in demagnetized position when it was de-energized

then up to 100 A/m magnetic field the flux density is about 0 so E1=0 and E2=0 and I2=0 since the second loop E=0.

So, no inrush current is expected in the secondary.

0=U-(E+Z*Iinrush)

U is the supply voltage, E it is the electromotive force in the primary or secondary windings and Z is the short-circuit impedance.

E=Φ*ω Φ=Bfe*A [A= magnetic core cross section area].The current will rise in time from 0 to Iinrush .

If the magnetic core was in demagnetized position when it was de-energized then up to 100 A/m magnetic field the flux density is about 0 then Φ=0 so E1=0 and so E2. So, no inrush current is expected in the secondary.

Iinrush=(U-E)/Z [ if E1=0 then Iinrush=U/Z] ; Z=R+jXe Xe=leakage magnetic flux reactance Xe=Le*ω it is considered independent of main flux level.
 

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