Integral closure in finite extension fields

In summary, the conversation discusses the concept of the integral closure of $R$ in a finite extension field $L$. The theorem states that for an element $\alpha$ in $L$, its minimal polynomial over $K$ has coefficients in the integral closure of $R$ in $K$, which is equal to $R$ if $R$ is integrally closed. The strategy given to solve the problem involves computing the minimal polynomial of $\alpha$ over $K(x)$ and using it to show that $\alpha$ is in $K[x][y]$, making it the integral closure of $R$ in $L$.
  • #1
pantboio
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Let $K=\mathbb{Q}[\omega]$ where $\omega^2+\omega+1=0$ and let $R$ be the polynomial ring $K[x]$. Let $L$ be the field $K(x)[y]$ where $y$ satisfies $y^3=1+x^2$.Which is the integral closure of $R$ in $L$, why?
 
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  • #2
Re: integral closure in finite extension fields

There is a theorem which says: let $R$ be a domain, le $K$ be the fraction field of $R$, and finally let $L$ be a finite extension ok $K$. Take an element $\alpha$ in $L$. Then $\alpha$ is algebraic over $K$ and call $m_{\alpha}(X)$ its minimal polynomial over $K$. Then the coefficients of $m_{\alpha}(X)$ lie in the integral closure of $R$ in $K$, hence in $R$ if we assume $R$ to be integrally closed.

My strategy to solve the problem i posted was:
1) take an element $\alpha$ in $L$ and express it in the most general form you can;
2) compute the minimal polynomial of $\alpha$ over $K(X)$.
3) now suppose $\alpha$ integral over $K[X]$, hence the coefficients of its minimal polynomial lie in the integral closure of $K[X]$ in $K(X)$, which is $K[X]$ itself.
4) deduce from 3) that the writing for $\alpha$ in 1) implies $\alpha\in K[X][Y]$ (my guess is that the integral closure of $K[x]$ in $L$ is $K[X][Y]$...)
 

FAQ: Integral closure in finite extension fields

What is integral closure in a finite extension field?

Integral closure in a finite extension field refers to the process of extending a smaller field, such as the rational numbers, to a larger field that still maintains the same algebraic properties. This extension is done by adding all the solutions to polynomial equations with coefficients from the smaller field.

Why is integral closure important in finite extension fields?

Integral closure is important because it allows us to study and understand properties of larger fields by first studying the smaller fields. This makes it easier to analyze and prove theorems about algebraic structures and their relationships.

How is integral closure related to algebraic extensions?

Integral closure is a special case of algebraic extensions, where the larger field is an algebraic extension of the smaller field. In other words, integral closure is a type of algebraic extension that preserves the algebraic properties of the smaller field.

Can integral closure be computed for any finite extension field?

Yes, integral closure can be computed for any finite extension field. This is because every finite extension field has a finite degree, which means that there is a finite number of elements that need to be added to the smaller field to create the larger field.

How is integral closure related to ring theory?

Integral closure is closely related to ring theory because it deals with the properties and structure of rings. In particular, it studies the properties of rings that are closed under polynomial extensions, which is a key concept in both integral closure and ring theory.

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