Integral of E dot dA - conceptual

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The discussion centers on calculating the integral of the electric field vector E and the differential area vector dA, with A given as a vector. Participants express confusion about how to derive dA from A and whether the problem is clear, noting that dA represents an infinitesimal area vector perpendicular to a surface. The integral of E dot dA is linked to electric flux, and it is clarified that the problem lacks a specified surface for integration. Ultimately, the calculation leads to a flux value of 8, but participants question the clarity and validity of the problem statement.
quantum13
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Homework Statement


A = 2i + 3j
E = 4i

determine the integral of E dot dA

Homework Equations


Integral calculus, vectors

The Attempt at a Solution


I don't understand why one could do this. The integral is of E and dA, not E and A. How can I use A to determine dA? Do I take its derivative? Then I would only get dA = 0.Also: This is part of an electric flux problem. Is this a basic of multivariate calculus? I'm indecisive on whether or not I should get a MV calc textbook - I don't have one yet, but I don't want basic questions like this holding me back either. I'm studying from Halliday's Fundamentals of Physics which apparently isn't a calculus heavy text.
 
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the question isn't very celar, but here's my 2 cents...

E is the electric field vector

Generally A represent some surface or area A. dA is vector in the direction normal to surface. If n is a unit vector in that direction, dA is a scalar infintesimal area, then

\texbf{dA} = \textbf{n}dA
with
A = \int dA

For a vector field E, the flux is given by
\Phi = \int \textbf{E} \bullet \textbf{dA}

physically the dot product means if the vector is parallel to the surface its contribution is zero, or maximum when it is perpindiuclar to the surface (passing through it). The integral just sums all the contributions across the whole surface.

so is there anymore to make the question clearer?
what area do you integrate over?
A is given as a vector - does this represent a normal to a plane or something?
 
quantum13 said:

Homework Statement


A = 2i + 3j
E = 4i

determine the integral of E dot dA

Homework Equations


Integral calculus, vectors


The Attempt at a Solution


I don't understand why one could do this. The integral is of E and dA, not E and A. How can I use A to determine dA? Do I take its derivative? Then I would only get dA = 0.


Also: This is part of an electric flux problem. Is this a basic of multivariate calculus? I'm indecisive on whether or not I should get a MV calc textbook - I don't have one yet, but I don't want basic questions like this holding me back either. I'm studying from Halliday's Fundamentals of Physics which apparently isn't a calculus heavy text.
You are right. The problem as stated makes no sense. I suggest you go back and reread the problem. It may be that you have overlooked something. "dA" should be a "vector differential of area" of some surface, not just a vector. Are you not given a surface to integrate over?
 
I'm sorry. dA is in fact an area vector perpendicular to a surface. However, the surface is definitely not stated. The answer is given as 8 (flux units). Does it make any mathematical sense to do this?

\Phi = \int \vec{E} \cdot \vec{dA}

<br /> \Phi = \vec{E} \cdot \int \vec{dA} <br />

<br /> \Phi = \vec{E} \cdot \vec{A} <br />Then
Phi = (4i) dot (2i + 3j)
= 8

No clue if this makes any sense or not but...?
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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