Integral of (ln(e^x + 1))^(1/3) / (e^x + 1)

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The integral of (ln(e^x + 1))^(1/3) / (e^x + 1) presents challenges in solving, particularly when using integration by parts, which leads to a repetitive loop. A suggested substitution is k = ln(e^x + 1), with the differential dk = dx(e^x)/(e^x + 1). Further discussion encourages letting u = ln(e^x + 1) to simplify the integral, aiming for a solution without x's in the resulting expression. Participants are exploring different approaches to resolve the integral effectively. The conversation highlights the complexity of the integral and the need for strategic substitutions.
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ravenea said:

Homework Statement



Integral of (ln(e^x + 1))^(1/3) / (e^x + 1)
See http://www2.wolframalpha.com/input/?i=integral+of+(ln(e**x+++1))**(1/3)/(e**x+++1)"


Homework Equations



N/A

The Attempt at a Solution



First, substitute k = ln(e^x + 1) dk = dx(e^x)/(e^x + 1)
Then, used integration by parts, but got to a loop...

If you let u = ln(ex+1) show us what you get for your du integral. There should be no x's in it.
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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