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Blues_MTA
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Homework Statement
Sec(x)/((ln(tan(x)+sec(x))^1/2)
We were instructed to find the integral
Homework Equations
Here is a link to the wolfram solution, i don't understand the steps they tookhttp://www.wolframalpha.com/input/?i=Integral+of+Sec%28x%29%2F%28%28ln%28sec%28x%29%2Btan%28x%29%29^1%2F2%29%29
The Attempt at a Solution
I understand that using the substitution method using u = Ln(tan(x)+sec(x))
du = Sec(x)^2+tan(x)Sec(x)/Sec(x)+Tan(x) dx
I do not understand how to substitute this and get 1/((u)^1/2) which is according to wolfram, I don't understand how the substitution method eliminates the Sec from the numerator, Later they evaluate that 1/(u^(1/2)) as 2((u)^1/2) can someone please explain these intermediate steps?