- #1
sapiental
- 118
- 0
g(x) = integral 0 to lnx (sin(t)+t^3/2))dt
find d/dx g(x):
let u = lnx
= sin(u) + u^3/2 du/dx
= sin(lnx)(1/x) + x^3/2(1/x)
Thanks
find d/dx g(x):
let u = lnx
= sin(u) + u^3/2 du/dx
= sin(lnx)(1/x) + x^3/2(1/x)
Thanks
Last edited: